A mixture of 1 mol N2 and 3 mol H2 reaches equilibrium in the Haber process after 0.5 mol of N2 has reacted. The mole fraction of NH3 in the equilibrium mixture (two decimals) is

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A mixture of 1 mol $N X_{2}$ and 3 mol $H X_{2}$ reaches equilibrium in the Haber process after 0.5 mol of $N X_{2}$ has reacted. The mole fraction of $NH X_{3}$ in the equilibrium mixture (two decimals) is

Moles at equilibrium:

N X_{2}

0.5,

H X_{2}

1.5,

NH X_{3}

1.0, total 3.0 mol. The mole fraction of

NH X_{3}

1.0/3.0 = 0.33