JEE Advanced levelSingle correct optionDifficulty 3 of 3pn179
In the brown ring complex [Fe(HX2O)X5NO]X2+, treat the nitrosyl ligand as NOX+ and assume a high-spin arrangement of d electrons. The oxidation state of iron and the spin-only magnetic moment (using n(n+2)) are
A+2 and 3.87BM
B+2 and 4.90BM
C+1 and 3.87BM
D+1 and 1.73BM
Answer: C
Charge: x+0+(+1)=+2, so x=+1. FeX+ is 3d7; high spin has t2g5eg2, giving 3 unpaired electrons. μ=3×5=15=3.87BM.