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MolSynapse / Question bank / p-Block Elements: Groups 13 and 14 / Boron compounds: diborane, boric acid, borax, boron halides

JEE Main levelSingle correct optionDifficulty 2 of 3pb175

Heating diborane with excess ammonia (high temperature) finally gives the compound

A $B (OH) X_{3}$
B $B X_{3} N X_{3} H X_{6}$ (borazine)
C $NH X_{4} BH X_{4}$
D $B X_{2} O X_{3}$

Answer: B

B X_{2} H X_{6}

with excess

NH X_{3}

forms

[BH X_{2} (NH X_{3}) X_{2}] X^{+} [BH X_{4}] X^{-}

, which on heating gives borazine:

3 B X_{2} H X_{6} + 6 NH X_{3} 3 [BH X_{2} (NH X_{3}) X_{2}] [BH X_{4}] Δ 2 B X_{3} N X_{3} H X_{6} + 12 H X_{2}

. Borazine is called inorganic benzene.

Practice p-Block Elements: Groups 13 and 14 More on Boron compounds: diborane, boric acid, borax, boron halides

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