Match the reactions of diborane in Column I with the products in Column II. Column I: (P) B2H6 + 6H2O; (Q) B2H6 + 3O2; (R) B2H6 + excess NH3, then heat; (S) B2H6 + 2N(CH3)3. Column II: (1) B2O3 + H2O; (2) H3BO3 + H2; (3) BH3.N(CH3)3; (4) B3N3H6 + H2.

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JEE Advanced levelSingle correct optionDifficulty 3 of 3pb178

Match the reactions of diborane in Column I with the products in Column II. Column I: (P) $B X_{2} H X_{6} + 6 H X_{2} O$ ; (Q) $B X_{2} H X_{6} + 3 O X_{2}$ ; (R) $B X_{2} H X_{6}$ + excess $NH X_{3}$ , then heat; (S) $B X_{2} H X_{6} + 2 N (CH X_{3}) X_{3}$ . Column II: (1) $B X_{2} O X_{3} + H X_{2} O$ ; (2) $H X_{3} BO X_{3} + H X_{2}$ ; (3) $BH X_{3} \cdot N (CH X_{3}) X_{3}$ ; (4) $B X_{3} N X_{3} H X_{6} + H X_{2}$ .

AP-2, Q-1, R-4, S-3
BP-1, Q-2, R-4, S-3
CP-2, Q-1, R-3, S-4
DP-4, Q-1, R-2, S-3

Answer: A

Hydrolysis gives boric acid and hydrogen (P-2). Combustion gives

B X_{2} O X_{3}

and water (Q-1). Excess ammonia followed by heating gives borazine and hydrogen (R-4). Trimethylamine cleaves the molecule symmetrically to the adduct (S-3).

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Answer: A

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