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JEE Advanced levelSingle correct optionDifficulty 3 of 3pb072

Which set correctly describes $Ni (CO) X_{4}$ ?

AOxidation state of Ni is 0; $s p^{3}$ ; tetrahedral; paramagnetic
BOxidation state of Ni is 0; $s p^{3}$ ; tetrahedral; diamagnetic
COxidation state of Ni is 0; $d s p^{2}$ ; square planar; diamagnetic
DOxidation state of Ni is $+ 4$ ; $s p^{3}$ ; tetrahedral; diamagnetic

Answer: B

CO

is neutral, so Ni is in the 0 state with configuration

3 d^{8} 4 s^{2}

. Pairing the

4 s

electrons into

3 d

gives

3 d^{10}

, and four

CO

ligands bind through

s p^{3}

hybrid orbitals. The shape is tetrahedral and there are no unpaired electrons, so it is diamagnetic.

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