JEE Advanced levelSingle correct optionDifficulty 3 of 3pb070
Red-hot coke is treated with steam to give water gas, and then all the CO formed is reacted with more steam (CO+HX2OCOX2+HX2). Starting from 1 mol of carbon and assuming complete conversion in both steps, the gas mixture finally contains
A1 mol HX2 and 1 mol COX2
B2 mol HX2 and 2 mol COX2
C2 mol HX2 and 1 mol COX2
D2 mol HX2 and 1 mol CO
Answer: C
Step 1: C+HX2OCO+HX2 gives 1 mol CO and 1 mol HX2. Step 2: the 1 mol of CO gives 1 mol COX2 and 1 further mol HX2. The total is 2 mol HX2 and 1 mol COX2.