Answer: B, C
Diborane has two bridge B−H−B banana bonds, so A is true. Terminal B−H bonds (about 119 pm) are shorter than bridging ones (about 134 pm), so B is false. Each B forms four bonds (two terminal and two bridge) and is sp3, so C is true. The two B and four terminal H lie in one plane, while the two bridging H lie above and below it, so D is false.