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JEE Main levelSingle correct optionDifficulty 2 of 3pb020

Hydrolysis of $BF X_{3}$ with water, after the $HF$ formed has reacted with unreacted $BF X_{3}$ , finally gives

A $B X_{2} H X_{6}$ and $HOF$
B $H X_{3} BO X_{3}$ and $HF$ only
C $B X_{2} O X_{3}$ and $HF$
D $H X_{3} BO X_{3}$ and $HBF X_{4}$

Answer: D

Water first gives

H X_{3} BO X_{3}

and

HF

; the

HF

then adds to unreacted

BF X_{3}

forming fluoroboric acid. Overall

4 BF X_{3} + 3 H X_{2} O H X_{3} BO X_{3} + 3 HBF X_{4}

.

Practice p-Block Elements: Groups 13 and 14 More on Boron compounds: diborane, boric acid, borax, boron halides

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