Answer: A, C
Saytzeff alkenes are more stable (more hyperconjugation), so statement 1 is right. 2-Bromobutane with alcoholic KOH gives mainly but-2-ene, so statement 2 is wrong. Bulky bases attack the least hindered H, so statement 3 is right. Hofmann elimination gives mainly the less substituted alkene, so statement 4 is wrong.