Answer: A, B, D
Ethoxide gives the tetrasubstituted Saytzeff alkene 2,3-dimethylbut-2-ene. The bulky tert-butoxide removes a methyl hydrogen, giving the Hofmann alkene 2,3-dimethylbut-1-ene. Beta-hydrogens: 6 on the two methyls plus 1 on C3, total 7. Statements 1, 2 and 4 are correct.