Answer: B
The secondary alcohol ionises (E1) to the secondary cation CHX3−CHX+−CH(CHX3)X2. A 1,2-hydride shift converts it into the tertiary cation CHX3−CHX2−CX+(CHX3)X2, which loses a proton mainly from the CH2 group (Saytzeff) to give 2-methylbut-2-ene.