Answer: C
The secondary cation CHX3−CHX+−CH(CHX3)X2 gives 3-methylbut-1-ene and 2-methylbut-2-ene. A 1,2-hydride shift gives the tertiary cation CHX3−CHX2−CX+(CHX3)X2, which gives 2-methylbut-2-ene (again) and 2-methylbut-1-ene. The distinct alkenes are 3-methylbut-1-ene, 2-methylbut-2-ene and 2-methylbut-1-ene: three.