The aryl dialkyl ether shown is heated with excess concentrated HI. Select all correct statements.

The compound is 1-tert-butoxy-4-methoxybenzene. The tert-butyl-oxygen bond breaks by $\mathrm{S}{}_{\mathrm{N}}1$ (stable tertiary cation), and the methyl-oxygen bond breaks by $\mathrm{S}{}_{\mathrm{N}}2$ (iodide attacks the unhindered methyl), not by $\mathrm{S}{}_{\mathrm{N}}1$, since a methyl cation is not accessible. The aryl C-O bonds are never cleaved, so the ring product is hydroquinone, not an iodoarene. Correct: first and third.