The single-enantiomer epoxide shown is reduced with $\mathrm{LiAlH}{}_4$ in ether, followed by aqueous work-up. Which product is formed?

The compound is (R)-styrene oxide. Hydride attacks the less hindered CH2, so the stereogenic benzylic C-O bond is not broken and the arrangement is retained. Writing the product as O[C@@H](C)c1ccccc1 and checking CIP gives S: in the epoxide CH2(O,H,H) outranks phenyl, but in the product phenyl outranks CH3, so the letter changes although the arrangement is retained. Product: (S)-1-phenylethanol.