Answer: D
The slow ionisation step does not involve the nucleophile, so the rate of disappearance of the chloride is (to a good approximation) unaffected by azide. The cation is intercepted in a fast second step by whichever nucleophile is available, so both azide (present at 0.10 M) and the solvent give products, and a mixture of (CHX3)X3C−NX3 and (CHX3)X3C−OH results.