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JEE Main levelSingle correct optionDifficulty 2 of 3o2086

Allyl chloride, $CH X_{2} = CH - CH X_{2} Cl$ , is treated with HBr in the presence of a peroxide. The major product is

A $CH X_{3} CH X_{2} CH X_{2} Cl$
B $CH X_{3} CHBrCH X_{2} Cl$
C $BrCH X_{2} CH X_{2} CH X_{2} Cl$
D $CH X_{2} = CH - CH X_{2} Br$

Answer: C

Br \cdot

adds to the terminal

= CH X_{2}

carbon, giving the secondary radical

BrCH X_{2} CH \cdot CH X_{2} Cl

. H abstraction from HBr gives 1-bromo-3-chloropropane, the anti-Markovnikov product.

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