In the free radical addition of HBr to an alkene in the presence of a peroxide, how many propagation steps make up one cycle of the chain?

Propagation consists of (1) addition of $\mathrm{Br}\cdot$ to the alkene to form a carbon radical and (2) abstraction of H from HBr by this radical, which gives the product and regenerates $\mathrm{Br}\cdot$. So there are two propagation steps.