Answer: A
Protonation gives the secondary cation (CHX3)X3C−CHX+−CHX3. A 1,2-methyl shift gives the tertiary cation (CHX3)X2CX+−CH(CHX3)X2, which is trapped by water. The major alcohol is 2,3-dimethylbutan-2-ol, not the unrearranged 3,3-dimethylbutan-2-ol.