JEE Advanced levelSingle correct optionDifficulty 3 of 3o1148
Acetaldehyde is treated in sequence with (i) HCN, trace KCN; (ii) LiAlHX4 in dry ether; (iii) dilute HX3OX+ work-up. The product is
A2-aminopropan-1-ol
Bpropane-1,2-diol
C3-aminopropan-1-ol
D1-aminopropan-2-ol
Answer: D
Step (i) gives CHX3−CH(OH)−CN. LiAlHX4 reduces the nitrile to a primary amine −CHX2NHX2 and does not touch the OH. The result is CHX3−CH(OH)−CHX2−NHX2, 1-aminopropan-2-ol. The carbon chain is unchanged by the reduction.