Acetone is subjected to (i) NaCN, dilute H2SO4; (ii) H3O+, heat (complete hydrolysis); (iii) concentrated H2SO4, heat. The final product is

2-methylprop-2-enoic acid (methacrylic acid)

3-hydroxy-2-methylpropanoic acid

JEE Advanced levelSingle correct optionDifficulty 3 of 3o1145

Acetone is subjected to (i) $NaCN$ , dilute $H X_{2} SO X_{4}$ ; (ii) $H X_{3} O X^{+}$ , heat (complete hydrolysis); (iii) concentrated $H X_{2} SO X_{4}$ , heat. The final product is

Step (i) gives acetone cyanohydrin

(CH X_{3}) X_{2} C (OH) - CN

. Step (ii) hydrolyses

- CN

- COOH

giving

(CH X_{3}) X_{2} C (OH) - COOH

. Step (iii) dehydrates the tertiary alcohol to the alkene

CH X_{2} = C (CH X_{3}) - COOH