Answer: D
The ketone is masked as a ketal, which is inert to Grignard reagents. Excess CHX3MgBr converts the ester into the tertiary alcohol −C(CHX3)X2OH, losing the ethoxy group. Aqueous acid in step (iii) removes the ketal and restores the ketone, giving CHX3−CO−CHX2CHX2−C(CHX3)X2−OH. Without protection both groups would react to give the diol.