For hydration in water at 298 K, K = [gem-diol]/[carbonyl] has the values 2000 for HCHO, 1.0 for CH3CHO and 0.0014 for CH3COCH3. Which statements follow?

Formaldehyde is more than 99.9% hydrated at equilibrium.

Acetaldehyde is about 50% hydrated at equilibrium.

Acetone is only about 0.14% hydrated at equilibrium.

Formaldehyde is more than 99.9% hydrated at equilibrium.

Acetone is hydrated to a larger extent than acetaldehyde.

Acetaldehyde is about 50% hydrated at equilibrium.

Acetone is only about 0.14% hydrated at equilibrium.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3o1105

For hydration in water at 298 K, $K = [gem-diol] / [carbonyl]$ has the values 2000 for $HCHO$ , 1.0 for $CH X_{3} CHO$ and 0.0014 for $CH X_{3} COCH X_{3}$ . Which statements follow?

Percentage hydrate

= 100 K / (1 + K)

: for

K = 2000

this is 99.95%, for

K = 1.0

it is 50.0%, and for

K = 0.0014

it is 0.14%. Acetone, with the smallest

K

, is the least hydrated of the three, so the last statement is false.