The diamide shown is completely converted to the diamine by the Hofmann bromamide reaction, each amide group following RCONH2 + Br2 + 4NaOH -> RNH2 + Na2CO3 + 2NaBr + 2H2O. How many moles of Br2 are consumed per mole of the diamide shown? Give your answer as an integer.

JEE Main levelNumerical answerDifficulty 2 of 3nc240

The diamide shown is completely converted to the diamine by the Hofmann bromamide reaction, each amide group following $RCONH X_{2} + Br X_{2} + 4 NaOH RNH X_{2} + Na X_{2} CO X_{3} + 2 NaBr + 2 H X_{2} O$ . How many moles of $Br X_{2}$ are consumed per mole of the diamide shown? Give your answer as an integer.

Numerical answer type, tolerance 0.5.

The compound shown has two amide groups. Each follows the given equation and uses one

Br X_{2}

. Total

Br X_{2}

= 2 x 1 = 2 mol per mole of diamide.