The diamide shown is subjected to Hofmann bromamide degradation (excess Br2/NaOH). Which structure is the product?

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The diamide shown is subjected to Hofmann bromamide degradation (excess $Br X_{2}$ / $NaOH$ ). Which structure is the product?

The compound shown is adipamide (hexanediamide). Each of the two

CONH X_{2}

groups loses its carbonyl carbon, giving a diamine with two fewer carbons: six carbons become four, i.e. butane-1,4-diamine.