Answer: B, C
The compound shown is phthalimide. The Gabriel route needs SN2 on a primary alkyl or benzylic halide, giving primary amines only. Butylamine (A) and benzylamine (D) are accessible. Tert-butylamine (B) would need a tertiary halide, which eliminates, and aniline (C) would need an aryl halide, which does not undergo SN2.