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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3nc165

Which pairs of reducing conditions and the major product from nitrobenzene are correctly matched?

A $Zn / NH X_{4} Cl$ (aqueous) : N-phenylhydroxylamine
B $Zn / NaOH$ : aniline
CElectrolytic reduction in strongly acidic medium : 4-aminophenol
D $LiAlH X_{4}$ : azobenzene

Answer: A, C, D

Neutral Zn/NH4Cl stops at N-phenylhydroxylamine, electrolytic reduction in strong acid gives 4-aminophenol (hydroxylamine rearranges), and LiAlH4 gives azobenzene. Zn with NaOH (alkaline medium) gives hydrazobenzene via azoxy and azo compounds, not aniline, so (B) is wrong.

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