Ethanenitrile, $\mathrm{CH}{}_3\mathrm{CN}$, is reduced with $\mathrm{LiAlH}{}_4$. The product is:

Reduction of a nitrile $\mathrm{RCN}$ with $\mathrm{LiAlH}{}_4$ or $\mathrm{H}{}_2/\mathrm{Ni}$ gives the primary amine $\mathrm{RCH}{}_2\mathrm{NH}{}_2$, which has one carbon more than the alkyl group $\mathrm{R}$ of the halide it came from. Here $\mathrm{CH}{}_3\mathrm{CN}$ gives ethylamine $\mathrm{CH}{}_3\mathrm{CH}{}_2\mathrm{NH}{}_2$. The aldehyde forms only with Stephen reduction ($\mathrm{SnCl}{}_2/\mathrm{HCl}$).