Acetamide, CH3CONH2, is treated with Br2 + NaOH (Hofmann bromamide degradation). The organic product is:

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Acetamide, $CH X_{3} CONH X_{2}$ , is treated with $Br X_{2} + NaOH$ (Hofmann bromamide degradation). The organic product is:

Hofmann bromamide degradation converts

RCONH X_{2}

into

RNH X_{2}

with loss of the carbonyl carbon as carbonate. Acetamide has two carbons, so the amine has one carbon, giving methylamine

CH X_{3} NH X_{2}