A mixture of $1.0 mol$ $H X_{2}$ and $1.0 mol$ $O X_{2}$ is sparked so that $2 H X_{2} + O X_{2} 2 H X_{2} O$ goes to completion. Water remains as vapour at the final temperature. The average molar mass of the final gaseous mixture is (H = 1, O = 16)

A $22.67 g mo l^{- 1}$
B $17.00 g mo l^{- 1}$
C $32.00 g mo l^{- 1}$
D $25.00 g mo l^{- 1}$

Answer: A

H2 is limiting: 1.0 mol H2 uses 0.5 mol O2 and gives 1.0 mol H2O(g); 0.5 mol O2 is left. Final gas: 1.0 mol H2O (18 g) + 0.5 mol O2 (16 g) = 34 g in 1.5 mol. Average M = 34/1.5 = 22.67 g/mol.

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A mixture of 1.0 mol HX2​ and 1.0 mol OX2​ is sparked so that 2HX2​+OX2​​2HX2​O goes to completion. Water remains as vapour at the final temperature. The average molar mass of the final gaseous mixture is (H = 1, O = 16)

Answer: A

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A mixture of $1.0 mol$ $H X_{2}$ and $1.0 mol$ $O X_{2}$ is sparked so that $2 H X_{2} + O X_{2} 2 H X_{2} O$ goes to completion. Water remains as vapour at the final temperature. The average molar mass of the final gaseous mixture is (H = 1, O = 16)