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JEE Advanced levelSingle correct optionDifficulty 3 of 3mc213

$10.0 L$ of a mixture of CO and $CO X_{2}$ at STP has a vapour density of $17$ . It is passed through excess KOH solution, which absorbs only $CO X_{2}$ . The volume of gas that remains at STP is (C = 12, O = 16)

A $3.75 L$
B $6.25 L$
C $5.00 L$
D $7.50 L$

Answer: B

M(mix) = 34. With x = mole (volume) fraction of CO2: 44x + 28(1 - x) = 34, so x = 0.375. CO2 = 3.75 L is absorbed; CO left = 10.0 - 3.75 = 6.25 L.

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