12 g of carbon is burned in 20 g of O2, so that the products are only CO and CO2 and all the carbon and oxygen are consumed. Find the mass of CO formed in grams, to the nearest integer (C = 12, O = 16).

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JEE Advanced levelNumerical answerDifficulty 3 of 3mc197

$12 g$ of carbon is burned in $20 g$ of $O X_{2}$ , so that the products are only $CO$ and $CO X_{2}$ and all the carbon and oxygen are consumed. Find the mass of CO formed in grams, to the nearest integer (C = 12, O = 16).

Numerical answer type, answer in g, tolerance 0.5.

Answer: 21 g

n(C) = 1.00 mol; n(O2) = 0.625 mol. Let CO2 = a mol and CO = b mol: a + b = 1 and a + b/2 = 0.625. Subtracting gives b/2 = 0.375, so b = 0.75 mol. Mass of CO = 0.75 x 28 = 21 g.

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12 g of carbon is burned in 20 g of OX2​, so that the products are only CO and COX2​ and all the carbon and oxygen are consumed. Find the mass of CO formed in grams, to the nearest integer (C = 12, O = 16).

Answer: 21 g

More questions on Limiting reagent, percent yield and percent excess

$12 g$ of carbon is burned in $20 g$ of $O X_{2}$ , so that the products are only $CO$ and $CO X_{2}$ and all the carbon and oxygen are consumed. Find the mass of CO formed in grams, to the nearest integer (C = 12, O = 16).