MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Mole Concept
/
Empirical and molecular formula, percentage composition
NEET level
Single correct option
Difficulty 1 of 3
mc168
A hydrocarbon has empirical formula
CH
X
2
and molar mass
84
g
mo
l
−
1
. Its molecular formula is (C = 12, H = 1)
A
C
X
5
H
X
10
B
C
X
7
H
X
14
C
C
X
6
H
X
12
D
C
X
3
H
X
6
Answer: C
Empirical formula mass of CH2 = 14. n = 84/14 = 6. Molecular formula = (CH2)6 = C6H12.
Practice Mole Concept
More on Empirical and molecular formula, percentage composition
Previous question
Next question
More questions on Empirical and molecular formula, percentage composition
A sample of 4.88 g of hydrated barium chloride, BaCl2.xH2O, loses 0.72 g of water completely on heating (Ba = 137, Cl = 35.5, O = 16, H = 1)...
JEE Advanced level
The percentage by mass of nitrogen in urea, CO(NH2)2, is closest to (C = 12, H = 1, N = 14, O = 16)
NEET level
A compound contains 40% C, 6.67% H and 53.33% O by mass. Its empirical formula is (C = 12, H = 1, O = 16)
NEET level
The percentage of water of crystallisation in CuSO4.5H2O is nearly (Cu = 63.5, S = 32, O = 16, H = 1)
NEET level
Complete combustion of 0.74 g of an organic compound containing only C, H and O gives 1.76 g of CO2 and 0.90 g of H2O. The empirical formula...
JEE Main level
Calculate the mass of iron, in grams, present in 1.00 kg of pure Fe3O4 (Fe = 56, O = 16). Give the answer to the nearest integer.
JEE Main level