MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Mole Concept
/
Concentration terms (molarity, molality, mole fraction, ppm) and dilution
NEET level
Single correct option
Difficulty 1 of 3
mc075
100
mL
of
2.0
M
HCl
is diluted with water to a total volume of
500
mL
. The new molarity is
A
0.4
M
B
10
M
C
0.5
M
D
1
M
Answer: A
M
1
V
1
=
M
2
V
2
, so
M
2
=
2.0
×
100/500
=
0.4
M.
Practice Mole Concept
More on Concentration terms (molarity, molality, mole fraction, ppm) and dilution
Previous question
Next question
More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution
4 g of NaOH (40 g/mol) is dissolved in water to make 500 mL of solution. Its molarity is
NEET level
A solution contains 46 g of ethanol (46 g/mol) and 36 g of water (18 g/mol). The mole fraction of ethanol is
NEET level
A 500 g sample of water contains 2.5 mg of fluoride ions. The concentration in ppm (by mass) is
NEET level
18 g of glucose (180 g/mol) is dissolved in 250 g of water. The molality of the solution is
JEE Main level
Concentrated sulfuric acid is 98% H2SO4 by mass with density 1.84 g/mL. Taking H2SO4=98 g/mol, its molarity is
JEE Main level
200 mL of 0.50 M HCl is mixed with 300 mL of 1.0 M HCl (volumes additive). The molarity of the mixture is
JEE Main level