Aniline is made from benzene in two steps: $C X_{6} H X_{6} C X_{6} H X_{5} NO X_{2}$ (80% yield) and $C X_{6} H X_{5} NO X_{2} C X_{6} H X_{5} NH X_{2}$ (75% yield). Starting from 15.6 g of benzene ( $M = 78$ ), find the mass of aniline ( $M = 93$ ) obtained in grams, to two decimal places. Each step is 1 : 1 in moles.

Numerical answer type, answer in g, tolerance 0.02.

Answer: 11.16 g

Moles of benzene = 15.6/78 = 0.2. Nitrobenzene = 0.2 x 0.80 = 0.16 mol. Aniline = 0.16 x 0.75 = 0.12 mol. Mass = 0.12 x 93 = 11.16 g.