MolSynapsequestion bank
MolSynapse / Question bank / Mole Concept / Stoichiometry of single and sequential reactions
JEE Advanced levelOne or more correct optionsDifficulty 3 of 3mc156

4.8 g of magnesium () is added to a solution containing 0.30 mol of HCl: . Which statements are correct? Use 22.4 L/mol at STP.

  1. AMass of Mg left over is 1.2 g
  2. B formed is 0.20 mol
  3. CHCl is the limiting reagent
  4. D liberated at STP is 3.36 L

Answer: A, C, D

Moles of Mg = 0.20; HCl needs only 0.30/2 = 0.15 mol Mg, so HCl is limiting (true). = 0.15 mol = 3.36 L (true). Mg left = (0.20 - 0.15) x 24 = 1.2 g (true). = 0.15 mol, not 0.20 (false).
Practice Mole Concept More on Stoichiometry of single and sequential reactions

More questions on Stoichiometry of single and sequential reactions