JEE Advanced levelOne or more correct optionsDifficulty 3 of 3mc156
4.8 g of magnesium (Mg=24) is added to a solution containing 0.30 mol of HCl: Mg+2HClMgClX2+HX2. Which statements are correct? Use 22.4 L/mol at STP.
AMass of Mg left over is 1.2 g
BMgClX2 formed is 0.20 mol
CHCl is the limiting reagent
DHX2 liberated at STP is 3.36 L
Answer: A, C, D
Moles of Mg = 0.20; HCl needs only 0.30/2 = 0.15 mol Mg, so HCl is limiting (true). HX2 = 0.15 mol = 3.36 L (true). Mg left = (0.20 - 0.15) x 24 = 1.2 g (true). MgClX2 = 0.15 mol, not 0.20 (false).