Iron is produced from $\mathrm{Fe}{}_2\mathrm{O}{}_3$ by aluminothermy, $2\mathrm{Al}+\mathrm{Fe}{}_2\mathrm{O}{}_3\to \mathrm{Al}{}_2\mathrm{O}{}_3+2\mathrm{Fe}$. To obtain $2.24\mathrm{kg}$ of iron (Fe = 56, Al = 27, O = 16), the masses of aluminium consumed and of $\mathrm{Al}{}_2\mathrm{O}{}_3$ formed are respectively

1. A$540\mathrm{g}$ and $2040\mathrm{g}$
2. B$1080\mathrm{g}$ and $1020\mathrm{g}$
3. C$2160\mathrm{g}$ and $4080\mathrm{g}$
4. D$1080\mathrm{g}$ and $2040\mathrm{g}$