Answer: A
Charge is 19.3×5000=96500 C=1.00 mol e−. Per gram of anode the electrons supplied are 2(0.800/63.5+0.150/65)=0.02981 mol, so 33.5 g of anode dissolves, releasing 26.8 g Cu and 5.03 g Zn into solution. The cathode deposits 0.500 mol=31.75 g Cu, so the electrolyte loses 31.75−26.83=4.9 g of Cu.