In a Bessemer converter, 477 g of pure Cu2S (Cu = 63.5, S = 32) is converted into copper by the sequence 2Cu2S + 3O2 -> 2Cu2O + 2SO2 and Cu2S + 2Cu2O -> 6Cu + SO2, using only the oxygen of the blast. The mass of copper obtained and the volume of O2 at STP consumed are respectively

JEE Advanced levelSingle correct optionDifficulty 3 of 3mt153

In a Bessemer converter, $477 g$ of pure $Cu X_{2} S$ (Cu = 63.5, S = 32) is converted into copper by the sequence $2 Cu X_{2} S + 3 O X_{2} 2 Cu X_{2} O + 2 SO X_{2}$ and $Cu X_{2} S + 2 Cu X_{2} O 6 Cu + SO X_{2}$ , using only the oxygen of the blast. The mass of copper obtained and the volume of $O X_{2}$ at STP consumed are respectively

Adding

2 Cu X_{2} S + 3 O X_{2} 2 Cu X_{2} O + 2 SO X_{2}

and

Cu X_{2} S + 2 Cu X_{2} O 6 Cu + SO X_{2}

gives

3 Cu X_{2} S + 3 O X_{2} 6 Cu + 3 SO X_{2}

. The molar mass of

Cu X_{2} S

159

, so

477 g

3.00 mol

, giving

6.00 mol

= 381 g

and consuming

3.00 mol

O X_{2} = 67.2 L