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JEE Advanced levelSingle correct optionDifficulty 3 of 3mt151

A metal M occurs as a sulphide ore concentrated by froth flotation. The ore is roasted, the oxide is heated with coke near and M leaves the furnace as vapour (boiling point ). The metal also precipitates gold from solution. Roasting of the pure sulphide (M = 65, S = 32) at STP gives what volume of , and what mass of M is obtained on complete reduction of the oxide?

  1. A of and of Zn
  2. B of and of Zn
  3. C of and of Zn
  4. D of and of Zn

Answer: C

A volatile metal obtained by coke reduction at that displaces gold is zinc, so the ore is (molar mass ). is . From , gives , i.e. , and ZnO, which gives Zn.
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