JEE Advanced levelSingle correct optionDifficulty 3 of 3mt147
Gold is leached by 4Au+8NaCN+OX2+2HX2O4Na[Au(CN)X2]+4NaOH and recovered by 2Na[Au(CN)X2]+ZnNaX2[Zn(CN)X4]+2Au. For 4.925g of gold (Au = 197, Zn = 65, Na = 23, C = 12, N = 14), the masses of NaCN consumed in leaching and of zinc consumed in precipitation are respectively
A1.23g and 0.81g
B2.45g and 1.63g
C4.90g and 0.41g
D2.45g and 0.81g
Answer: D
n(Au)=4.925/197=0.0250mol. Leaching needs 2molNaCN per Au, so 0.0500mol×49=2.45g. Precipitation needs 1mol Zn per 2mol Au, so 0.0125mol×65=0.8125≈0.81g.