JEE Advanced levelSingle correct optionDifficulty 3 of 3mt146
For 2Zn+OX22ZnO, ΔH∘=−700kJ and ΔS∘=−0.200kJK−1; for 2C+OX22CO, ΔH∘=−221kJ and ΔS∘=+0.180kJK−1 (both per mole of OX2, taken as temperature independent). The lowest temperature at which ZnO+CZn+CO becomes spontaneous is closest to
A630K
B1260K
C2520K
D3500K
Answer: B
Subtract the zinc equation from the carbon equation and halve it: ΔH∘=(−221+700)/2=+239.5kJ and ΔS∘=(0.180+0.200)/2=0.190kJK−1. Spontaneity needs ΔH∘−TΔS∘<0, so T>239.5/0.190≈1260K.