JEE Advanced levelSingle correct optionDifficulty 3 of 3mt105
For oxide formation (per mole of OX2, in kJ, T in K): 2M+OX22MO, ΔG∘=−560+0.20T; 2C+OX22CO, ΔG∘=−225−0.175T. The ΔG∘ of MO+CM+CO at 1200 K, per mole of MO, is
A−377.5kJ
B−57.5kJ
C−115.0kJ
D57.5kJ
Answer: B
At 1200 K, ΔGCO=−225−210=−435 and ΔGMO=−560+240=−320kJ. The coupled reaction for 2 mol MO is −435−(−320)=−115 kJ, so per mole of MO it is −57.5kJ. Negative, so carbon reduces the oxide at 1200 K.