Lead is obtained from impure galena by partial roasting ($2\mathrm{PbS}+3\mathrm{O}{}_2\to 2\mathrm{PbO}+2\mathrm{SO}{}_2$) followed by self-reduction ($\mathrm{PbS}+2\mathrm{PbO}\to 3\mathrm{Pb}+\mathrm{SO}{}_2$). Assume all lead of the ore ends up as metal. Using Pb = 207 and S = 32, the mass of galena ore containing $80\%$ $\mathrm{PbS}$ needed for $414\mathrm{kg}$ of lead is

1. A$318.7\mathrm{kg}$
2. B$896.2\mathrm{kg}$
3. C$478.0\mathrm{kg}$
4. D$597.5\mathrm{kg}$