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JEE Advanced levelSingle correct optionDifficulty 3 of 3nm262

What is the name of the compound shown? Use von Baeyer rules: bridges in decreasing order in the brackets, numbering from a bridgehead.

  1. A2,2-dichlorobicyclo[4.1.0]heptane
  2. B7,7-dichlorobicyclo[4.1.0]heptane
  3. C8,8-dichlorobicyclo[4.2.0]octane
  4. D7,7-dichlorobicyclo[1.4.0]heptane

Answer: B

The compound is 7,7-dichlorobicyclo[4.1.0]heptane. The fused cyclohexane/cyclopropane skeleton has bridges of 4, 1 and 0 carbons. The numbering goes C1, the four-carbon bridge C2 to C5, bridgehead C6, then the one-carbon bridge C7, which carries both chlorines.
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