What is the von Baeyer name of the compound shown?

Abicyclo[3.3.0]octane
Bbicyclo[3.2.1]octane
Cbicyclo[2.2.2]octane
Dbicyclo[4.2.0]octane

Answer: C

The compound is bicyclo[2.2.2]octane. Its two bridgeheads are connected by three bridges of two carbons each, and the skeleton has 2 + 2 + 2 + 2 = 8 carbons.

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