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JEE Main levelSingle correct optionDifficulty 2 of 3nm252

What is the name of the compound shown? Number from the ring atom next to the spiro atom, in the smaller ring first, and give substituents the lowest locants.

  1. A1-methylspiro[4.3]octane
  2. B1-methylspiro[3.4]octane
  3. C5-methylspiro[3.4]octane
  4. D2-methylspiro[3.4]octane

Answer: B

The compound is 1-methylspiro[3.4]octane. The smaller ring (cyclobutane) is numbered first, starting next to the spiro atom: C1, C2, C3, then spiro C4, then C5 to C8 in the five-membered ring. The methyl sits on the carbon adjacent to the spiro atom in the small ring, so its locant is 1.
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