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What is the IUPAC name of the compound shown?

  1. A2-methylpent-3-ene
  2. B2-methylpent-2-ene
  3. C3-methylpent-2-ene
  4. D4-methylpent-2-ene

Answer: D

The compound is 4-methylpent-2-ene. The double bond must get the lowest locant, so numbering starts at the CH3 end next to the double bond (locant 2, not 3). The methyl group then sits on C4.
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