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JEE Main levelSingle correct optionDifficulty 2 of 3nm226

What is the IUPAC name of the compound shown? Number the chain so that the set of multiple-bond locants is lowest; if the sets tie, give the double bond the lower locant.

  1. Apent-3-en-1-yne
  2. Bpent-4-en-1-yne
  3. Cpent-4-en-2-yne
  4. Dpent-1-en-3-yne

Answer: D

The compound is pent-1-en-3-yne. Numbering from the CH2= end gives the multiple-bond locants {1,3}, from the CH3 end {2,4}; the set {1,3} is lower. In the name the ene precedes the yne.
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