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Ionic Equilibrium I
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Solubility product and simple solubility calculations
JEE Advanced level
Numerical answer
Difficulty 3 of 3
ie206
A solution is saturated with both
AgCl
(
K
s
p
=
1.8
×
1
0
−
10
) and
AgBr
(
K
s
p
=
5.0
×
1
0
−
13
). Find
[
Br
X
−
]
in units of
1
0
−
8
mol
L
−
1
(two decimals).
Numerical answer type, answer in x 10^-8 mol/L, tolerance 0.03.
Answer: 3.72 x 10^-8 mol/L
Shared
Ag
X
+
obeys
[
Ag
X
+
]
2
=
K
1
+
K
2
, so
[
Ag
X
+
]
=
1.3
×
1
0
−
5
M
. Then
[
Br
X
−
]
=
5.0
×
1
0
−
13
/1.3
×
1
0
−
5
=
3.7
×
1
0
−
8
M
.
Practice Ionic Equilibrium I
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