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Ionic Equilibrium I
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Solubility product and simple solubility calculations
JEE Advanced level
Single correct option
Difficulty 3 of 3
ie202
The solubility of
Mg
(
OH
)
X
2
(
K
s
p
=
1.6
×
1
0
−
11
) in a buffer solution maintained at pH 11 (298 K) is
A
1.6
×
1
0
−
4
M
B
1.6
×
1
0
−
5
M
C
1.6
×
1
0
−
8
M
D
4.0
×
1
0
−
6
M
Answer: B
At pH 11,
[
OH
X
−
]
=
1
0
−
3
M
is fixed by the buffer, so
s
=
[
Mg
X
2
+
]
=
K
s
p
/
[
OH
X
−
]
2
=
1.6
×
1
0
−
11
/1
0
−
6
=
1.6
×
1
0
−
5
M
.
Practice Ionic Equilibrium I
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